What are the solutions to the equation 4x^2-13=9x ?

The solutions to the equation 4x^2-13=9x are x= 13/4 ,x=-1

Find the zeros of 4x^2-13=9x

The zeros of 4x^2-13=9x are x= 13/4 ,x=-1

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4 x^{2} - 13 = 9 x

x = \frac{13}{4}, x = - 1

Decimal Notation

x = 3.25, x = - 1

Solution steps

4 x^{2} - 13 = 9 x

Move

9 x

to the left side

4 x^{2} - 13 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 9 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 13 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 13) = 17

x_{1, 2} = \frac{- ( - 9 ) \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 17}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 17}{2 \cdot 4}

x = \frac{- ( - 9 ) + 17}{2 \cdot 4} : \frac{13}{4}

x = \frac{- ( - 9 ) - 17}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{13}{4}, x = - 1

(x + 5)^{2} - 3 (x + 5) - 10 = 0

w^{2} = 12 w

8 x^{2} + 20 x = 48

d^{2} + 34 d = 0

7 x^{2} + 29 x - 30 = 0

What are the solutions to the equation 4x^2-13=9x ?
The solutions to the equation 4x^2-13=9x are x= 13/4 ,x=-1
Find the zeros of 4x^2-13=9x
The zeros of 4x^2-13=9x are x= 13/4 ,x=-1