What are the solutions to the equation x^2+4x+45=0 ?

The solutions to the equation x^2+4x+45=0 are x=-2+sqrt(41)i,x=-2-sqrt(41)i

Find the zeros of x^2+4x+45=0

The zeros of x^2+4x+45=0 are x=-2+sqrt(41)i,x=-2-sqrt(41)i

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x^{2} + 4 x + 45 = 0

x = - 2 + 41 i, x = - 2 - 41 i

Solution steps

x^{2} + 4 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 45 : 241 i

x_{1, 2} = \frac{- 4 \pm 2 41 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 41 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 41 i}{2 \cdot 1}

x = \frac{- 4 + 2 41 i}{2 \cdot 1} : - 2 + 41 i

x = \frac{- 4 - 2 41 i}{2 \cdot 1} : - 2 - 41 i

The solutions to the quadratic equation are:

x = - 2 + 41 i, x = - 2 - 41 i

x^{2} - 32 x + 64 = 0

- 3 x^{2} - 7 + 2 x = - 11

4 x = 6 x^{2}

3 x^{2} - 5 x + c = 0

g^{2} = 6 0^{2} + 1 5^{2}

What are the solutions to the equation x^2+4x+45=0 ?
The solutions to the equation x^2+4x+45=0 are x=-2+sqrt(41)i,x=-2-sqrt(41)i
Find the zeros of x^2+4x+45=0
The zeros of x^2+4x+45=0 are x=-2+sqrt(41)i,x=-2-sqrt(41)i