What are the solutions to the equation -3x^2-7+2x=-11 ?

The solutions to the equation -3x^2-7+2x=-11 are x=-(-1+sqrt(13))/3 ,x=(1+sqrt(13))/3

Find the zeros of -3x^2-7+2x=-11

The zeros of -3x^2-7+2x=-11 are x=-(-1+sqrt(13))/3 ,x=(1+sqrt(13))/3

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- 3 x^{2} - 7 + 2 x = - 11

x = - \frac{- 1 + 13}{3}, x = \frac{1 + 13}{3}

Decimal Notation

x = - 0.86851 \dots, x = 1.53518 \dots

Solution steps

- 3 x^{2} - 7 + 2 x = - 11

Move

11

to the left side

- 3 x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) \cdot 4}{2 ( - 3 )}

2^{2} - 4 (- 3) \cdot 4 = 213

x_{1, 2} = \frac{- 2 \pm 2 13}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 13}{2 ( - 3 )}, x_{2} = \frac{- 2 - 2 13}{2 ( - 3 )}

x = \frac{- 2 + 2 13}{2 ( - 3 )} : - \frac{- 1 + 13}{3}

x = \frac{- 2 - 2 13}{2 ( - 3 )} : \frac{1 + 13}{3}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 13}{3}, x = \frac{1 + 13}{3}

4 x = 6 x^{2}

3 x^{2} - 5 x + c = 0

g^{2} = 6 0^{2} + 1 5^{2}

9 z = 10 z^{2}

- 6 + 7 x - x^{2} = 0

What are the solutions to the equation -3x^2-7+2x=-11 ?
The solutions to the equation -3x^2-7+2x=-11 are x=-(-1+sqrt(13))/3 ,x=(1+sqrt(13))/3
Find the zeros of -3x^2-7+2x=-11
The zeros of -3x^2-7+2x=-11 are x=-(-1+sqrt(13))/3 ,x=(1+sqrt(13))/3