What are the solutions to the equation 4x^2-22+3x=0 ?

The solutions to the equation 4x^2-22+3x=0 are x=2,x=-11/4

Find the zeros of 4x^2-22+3x=0

The zeros of 4x^2-22+3x=0 are x=2,x=-11/4

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4 x^{2} - 22 + 3 x = 0

x = 2, x = - \frac{11}{4}

Decimal Notation

x = 2, x = - 2.75

Solution steps

4 x^{2} - 22 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 3 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 22 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 22) = 19

x_{1, 2} = \frac{- 3 \pm 19}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 19}{2 \cdot 4}, x_{2} = \frac{- 3 - 19}{2 \cdot 4}

x = \frac{- 3 + 19}{2 \cdot 4} : 2

x = \frac{- 3 - 19}{2 \cdot 4} : - \frac{11}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{11}{4}

x^{2} + 38 x = 0

4 x = - 2 x^{2} + 3

(5 x - 2)^{2} + 35 x - 14 = - 12

x^{2} + 8 x + 1 = 0

\frac{( 3 x - 7 ) ( x + 1 )}{2} = 8

What are the solutions to the equation 4x^2-22+3x=0 ?
The solutions to the equation 4x^2-22+3x=0 are x=2,x=-11/4
Find the zeros of 4x^2-22+3x=0
The zeros of 4x^2-22+3x=0 are x=2,x=-11/4