What are the solutions to the equation x^2+38x=0 ?

The solutions to the equation x^2+38x=0 are x=0,x=-38

Find the zeros of x^2+38x=0

The zeros of x^2+38x=0 are x=0,x=-38

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x^{2} + 38 x = 0

x = 0, x = - 38

Solution steps

x^{2} + 38 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 38 \pm 3 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3 8^{2} - 4 \cdot 1 \cdot 0 = 38

x_{1, 2} = \frac{- 38 \pm 38}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 38 + 38}{2 \cdot 1}, x_{2} = \frac{- 38 - 38}{2 \cdot 1}

x = \frac{- 38 + 38}{2 \cdot 1} : 0

x = \frac{- 38 - 38}{2 \cdot 1} : - 38

The solutions to the quadratic equation are:

x = 0, x = - 38

4 x = - 2 x^{2} + 3

(5 x - 2)^{2} + 35 x - 14 = - 12

x^{2} + 8 x + 1 = 0

\frac{( 3 x - 7 ) ( x + 1 )}{2} = 8

x^{2} = 7 x - 10

What are the solutions to the equation x^2+38x=0 ?
The solutions to the equation x^2+38x=0 are x=0,x=-38
Find the zeros of x^2+38x=0
The zeros of x^2+38x=0 are x=0,x=-38