What are the solutions to the equation 3x^2+6=-9x ?

The solutions to the equation 3x^2+6=-9x are x=-1,x=-2

Find the zeros of 3x^2+6=-9x

The zeros of 3x^2+6=-9x are x=-1,x=-2

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3 x^{2} + 6 = - 9 x

x = - 1, x = - 2

Solution steps

3 x^{2} + 6 = - 9 x

Move

9 x

to the left side

3 x^{2} + 6 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 9 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 6 = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 \cdot 3}, x_{2} = \frac{- 9 - 3}{2 \cdot 3}

x = \frac{- 9 + 3}{2 \cdot 3} : - 1

x = \frac{- 9 - 3}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

2 x^{2} + 4 x + 20 = 0

4 x^{2} - 9 = 9 x

x^{2} - 9 x + 17 = 0

y, f = 3 x^{3} - 2 x y + 5 y^{2}

2 x^{2} + 11 x - 4 = 0

What are the solutions to the equation 3x^2+6=-9x ?
The solutions to the equation 3x^2+6=-9x are x=-1,x=-2
Find the zeros of 3x^2+6=-9x
The zeros of 3x^2+6=-9x are x=-1,x=-2