What are the solutions to the equation 3r^2+4r+2=0 ?

The solutions to the equation 3r^2+4r+2=0 are r=-2/3+i(sqrt(2))/3 ,r=-2/3-i(sqrt(2))/3

Find the zeros of 3r^2+4r+2=0

The zeros of 3r^2+4r+2=0 are r=-2/3+i(sqrt(2))/3 ,r=-2/3-i(sqrt(2))/3

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3 r^{2} + 4 r + 2 = 0

r = - \frac{2}{3} + i \frac{2}{3}, r = - \frac{2}{3} - i \frac{2}{3}

Solution steps

3 r^{2} + 4 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

4^{2} - 4 \cdot 3 \cdot 2 : 22 i

r_{1, 2} = \frac{- 4 \pm 2 2 i}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- 4 + 2 2 i}{2 \cdot 3}, r_{2} = \frac{- 4 - 2 2 i}{2 \cdot 3}

r = \frac{- 4 + 2 2 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{2}{3}

r = \frac{- 4 - 2 2 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

r = - \frac{2}{3} + i \frac{2}{3}, r = - \frac{2}{3} - i \frac{2}{3}

x (20 - x) = 96

a x^{2} - 6 x + c = 0

x^{2} = 6^{2} + 1 0^{2}

x^{2} + 4 x + 4 = - 9

1 8^{2} = 1 2^{2} + x^{2}

What are the solutions to the equation 3r^2+4r+2=0 ?
The solutions to the equation 3r^2+4r+2=0 are r=-2/3+i(sqrt(2))/3 ,r=-2/3-i(sqrt(2))/3
Find the zeros of 3r^2+4r+2=0
The zeros of 3r^2+4r+2=0 are r=-2/3+i(sqrt(2))/3 ,r=-2/3-i(sqrt(2))/3