What are the solutions to the equation x^2+4x+4=-9 ?

The solutions to the equation x^2+4x+4=-9 are x=-2+3i,x=-2-3i

Find the zeros of x^2+4x+4=-9

The zeros of x^2+4x+4=-9 are x=-2+3i,x=-2-3i

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x^{2} + 4 x + 4 = - 9

x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

x^{2} + 4 x + 4 = - 9

Move

9

to the left side

x^{2} + 4 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 13 : 6 i

x_{1, 2} = \frac{- 4 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 6 i}{2 \cdot 1}

x = \frac{- 4 + 6 i}{2 \cdot 1} : - 2 + 3 i

x = \frac{- 4 - 6 i}{2 \cdot 1} : - 2 - 3 i

The solutions to the quadratic equation are:

x = - 2 + 3 i, x = - 2 - 3 i

1 8^{2} = 1 2^{2} + x^{2}

x^{2} - 2 x + 10 = 25

2 x^{2} - 14 x + 9 = 0

400 - x^{2} = 20 x + 100

x, 20 m^{2} = (2 x + 6 m) x

What are the solutions to the equation x^2+4x+4=-9 ?
The solutions to the equation x^2+4x+4=-9 are x=-2+3i,x=-2-3i
Find the zeros of x^2+4x+4=-9
The zeros of x^2+4x+4=-9 are x=-2+3i,x=-2-3i