What are the solutions to the equation 25q^2+40q+16=0 ?

The solutions to the equation 25q^2+40q+16=0 are q=-4/5

Find the zeros of 25q^2+40q+16=0

The zeros of 25q^2+40q+16=0 are q=-4/5

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25 q^{2} + 40 q + 16 = 0

q = - \frac{4}{5}

Decimal Notation

q = - 0.8

Solution steps

25 q^{2} + 40 q + 16 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

4 0^{2} - 4 \cdot 25 \cdot 16 = 0

q_{1, 2} = \frac{- 40 \pm 0}{2 \cdot 25}

q = \frac{- 40}{2 \cdot 25}

\frac{- 40}{2 \cdot 25} = - \frac{4}{5}

q = - \frac{4}{5}

The solution to the quadratic equation is:

q = - \frac{4}{5}

x^{(2)} + 11 x + 24 = 0

5 x^{2} + 4 = 3

5 x^{2} - 1 = 3 x^{2}

x, 4 x^{2} + x y = 16

x^{2} + 7 x + 4 = 0

What are the solutions to the equation 25q^2+40q+16=0 ?
The solutions to the equation 25q^2+40q+16=0 are q=-4/5
Find the zeros of 25q^2+40q+16=0
The zeros of 25q^2+40q+16=0 are q=-4/5