What are the solutions to the equation x^2=log_{2}(48)-log_{2}(3) ?

The solutions to the equation x^2=log_{2}(48)-log_{2}(3) are x=2,x=-2

Find the zeros of x^2=log_{2}(48)-log_{2}(3)

The zeros of x^2=log_{2}(48)-log_{2}(3) are x=2,x=-2

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x^{2} = lo g_{2} (48) - lo g_{2} (3)

x = 2, x = - 2

Solution steps

x^{2} = lo g_{2} (48) - lo g_{2} (3)

Simplify

lo g_{2} (48) - lo g_{2} (3) : 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x^{2} = 4 x - 13

16 r^{2} + 18 r + 5 = 0

(14 - b)^{3} + b^{3} = 812

10 = π r^{2}

4.9 x^{2} + 5 x - 10 = 0

What are the solutions to the equation x^2=log_{2}(48)-log_{2}(3) ?
The solutions to the equation x^2=log_{2}(48)-log_{2}(3) are x=2,x=-2
Find the zeros of x^2=log_{2}(48)-log_{2}(3)
The zeros of x^2=log_{2}(48)-log_{2}(3) are x=2,x=-2