What are the solutions to the equation a^2-8a=-15 ?

The solutions to the equation a^2-8a=-15 are a=5,a=3

Find the zeros of a^2-8a=-15

The zeros of a^2-8a=-15 are a=5,a=3

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a^{2} - 8 a = - 15

a = 5, a = 3

Solution steps

a^{2} - 8 a = - 15

Move

15

to the left side

a^{2} - 8 a + 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

a_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

a = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

a = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

a = 5, a = 3

10 x^{2} + 20 x = 0

30 = 0.000006 x^{2} - 0.02 x + 25

z^{2} + 6 z = 0

(x) = x^{2} + 2 x + 1

D, (D^{2} - 4 D + 5) 3 (D - 3) 4 y = 0

What are the solutions to the equation a^2-8a=-15 ?
The solutions to the equation a^2-8a=-15 are a=5,a=3
Find the zeros of a^2-8a=-15
The zeros of a^2-8a=-15 are a=5,a=3