What are the solutions to the equation z^2+6z=0 ?

The solutions to the equation z^2+6z=0 are z=0,z=-6

Find the zeros of z^2+6z=0

The zeros of z^2+6z=0 are z=0,z=-6

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z^{2} + 6 z = 0

z = 0, z = - 6

Solution steps

z^{2} + 6 z = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 0 = 6

z_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 6 + 6}{2 \cdot 1}, z_{2} = \frac{- 6 - 6}{2 \cdot 1}

z = \frac{- 6 + 6}{2 \cdot 1} : 0

z = \frac{- 6 - 6}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

z = 0, z = - 6

(x) = x^{2} + 2 x + 1

D, (D^{2} - 4 D + 5) 3 (D - 3) 4 y = 0

q^{2} + 3 q - 4 = 0

- 0.0013 x^{2} + x + 13 = 0

X^{2} + 10 X + 21 = 0

What are the solutions to the equation z^2+6z=0 ?
The solutions to the equation z^2+6z=0 are z=0,z=-6
Find the zeros of z^2+6z=0
The zeros of z^2+6z=0 are z=0,z=-6