What are the solutions to the equation solvefor D,(D^2-4D+5)3(D-3)4y=0 ?

The solutions to the equation solvefor D,(D^2-4D+5)3(D-3)4y=0 are D=2+i,D=2-i,D=3;\quad y\ne 0

Find the zeros of solvefor D,(D^2-4D+5)3(D-3)4y=0

The zeros of solvefor D,(D^2-4D+5)3(D-3)4y=0 are D=2+i,D=2-i,D=3;\quad y\ne 0

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solve for

D, (D^{2} - 4 D + 5) 3 (D - 3) 4 y = 0

D = 2 + i, D = 2 - i, D = 3; y \neq = 0

Solution steps

(D^{2} - 4 D + 5) \cdot 3 (D - 3) \cdot 4 y = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

D^{2} - 4 D + 5 = 0 or D - 3 = 0

Solve

D^{2} - 4 D + 5 = 0 : D = 2 + i, D = 2 - i

Solve

D - 3 = 0 : D = 3

The solutions are

D = 2 + i, D = 2 - i, D = 3; y \neq = 0

q^{2} + 3 q - 4 = 0

- 0.0013 x^{2} + x + 13 = 0

X^{2} + 10 X + 21 = 0

- 16 x^{2} + 272 x + 204 = 0

x, 26406.25 = (25 - 2 x) (1000 + 50 x)

What are the solutions to the equation solvefor D,(D^2-4D+5)3(D-3)4y=0 ?
The solutions to the equation solvefor D,(D^2-4D+5)3(D-3)4y=0 are D=2+i,D=2-i,D=3;\quad y\ne 0
Find the zeros of solvefor D,(D^2-4D+5)3(D-3)4y=0
The zeros of solvefor D,(D^2-4D+5)3(D-3)4y=0 are D=2+i,D=2-i,D=3;\quad y\ne 0