What are the solutions to the equation q^2+3q-4=0 ?

The solutions to the equation q^2+3q-4=0 are q=1,q=-4

Find the zeros of q^2+3q-4=0

The zeros of q^2+3q-4=0 are q=1,q=-4

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q^{2} + 3 q - 4 = 0

q = 1, q = - 4

Solution steps

q^{2} + 3 q - 4 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 4) = 5

q_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 3 + 5}{2 \cdot 1}, q_{2} = \frac{- 3 - 5}{2 \cdot 1}

q = \frac{- 3 + 5}{2 \cdot 1} : 1

q = \frac{- 3 - 5}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

q = 1, q = - 4

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What are the solutions to the equation q^2+3q-4=0 ?
The solutions to the equation q^2+3q-4=0 are q=1,q=-4
Find the zeros of q^2+3q-4=0
The zeros of q^2+3q-4=0 are q=1,q=-4