What are the solutions to the equation (x-2)^2+(x+4)^2=30^2 ?

The solutions to the equation (x-2)^2+(x+4)^2=30^2 are x=20,x=-22

Find the zeros of (x-2)^2+(x+4)^2=30^2

The zeros of (x-2)^2+(x+4)^2=30^2 are x=20,x=-22

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(x - 2)^{2} + (x + 4)^{2} = 3 0^{2}

x = 20, x = - 22

Solution steps

(x - 2)^{2} + (x + 4)^{2} = 3 0^{2}

Expand

(x - 2)^{2} + (x + 4)^{2} : 2 x^{2} + 4 x + 20

Expand

3 0^{2} : 900

2 x^{2} + 4 x + 20 = 900

Move

900

to the left side

2 x^{2} + 4 x - 880 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 880 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 880) = 84

x_{1, 2} = \frac{- 4 \pm 84}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 84}{2 \cdot 2}, x_{2} = \frac{- 4 - 84}{2 \cdot 2}

x = \frac{- 4 + 84}{2 \cdot 2} : 20

x = \frac{- 4 - 84}{2 \cdot 2} : - 22

The solutions to the quadratic equation are:

x = 20, x = - 22

2 x (x - 1) + 5 = 5 x^{2}

x^{2} + x - 6 = 2 x

20 x^{2} - 7 x - 3 = 0

50 x^{2} = 18

x, z = 3 x^{2} - 12 x + 2 y^{3} + 3 y^{2} - 12 y

What are the solutions to the equation (x-2)^2+(x+4)^2=30^2 ?
The solutions to the equation (x-2)^2+(x+4)^2=30^2 are x=20,x=-22
Find the zeros of (x-2)^2+(x+4)^2=30^2
The zeros of (x-2)^2+(x+4)^2=30^2 are x=20,x=-22