What are the solutions to the equation 0=(50+(x^2)/2+6x)/(2) ?

The solutions to the equation 0=(50+(x^2)/2+6x)/(2) are x=-6+8i,x=-6-8i

Find the zeros of 0=(50+(x^2)/2+6x)/(2)

The zeros of 0=(50+(x^2)/2+6x)/(2) are x=-6+8i,x=-6-8i

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0 = \frac{50 + \frac{x ^{2}}{2} + 6 x}{2}

x = - 6 + 8 i, x = - 6 - 8 i

Solution steps

0 = \frac{50 + \frac{x ^{2}}{2} + 6 x}{2}

Multiply both sides by

2

0 = 50 + \frac{x ^{2}}{2} + 6 x

Switch sides

50 + \frac{x ^{2}}{2} + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

\frac{1 \cdot x ^{2}}{2} + 6 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot \frac{1}{2} \cdot 50}{2 \cdot \frac{1}{2}}

Simplify

6^{2} - 4 \cdot \frac{1}{2} \cdot 50 : 8 i

x_{1, 2} = \frac{- 6 \pm 8 i}{2 \cdot \frac{1}{2}}

Separate the solutions

x_{1} = \frac{- 6 + 8 i}{2 \cdot \frac{1}{2}}, x_{2} = \frac{- 6 - 8 i}{2 \cdot \frac{1}{2}}

x = \frac{- 6 + 8 i}{2 \frac{1}{2}} : - 6 + 8 i

x = \frac{- 6 - 8 i}{2 \frac{1}{2}} : - 6 - 8 i

The solutions to the quadratic equation are:

x = - 6 + 8 i, x = - 6 - 8 i

x^{2} - 7 x + 6 = 0

x^{2} - 20 x + 9 = 0

y^{2} - 20 = 0

B, x^{2} - 5 x + A = (x + B)^{2}

(x + 4)^{2} + 7 = 0

What are the solutions to the equation 0=(50+(x^2)/2+6x)/(2) ?
The solutions to the equation 0=(50+(x^2)/2+6x)/(2) are x=-6+8i,x=-6-8i
Find the zeros of 0=(50+(x^2)/2+6x)/(2)
The zeros of 0=(50+(x^2)/2+6x)/(2) are x=-6+8i,x=-6-8i