What are the solutions to the equation solvefor B,x^2-5x+A=(x+B)^2 ?

The solutions to the equation solvefor B,x^2-5x+A=(x+B)^2 are B=sqrt(x^2-5x+A)-x,B=-sqrt(x^2-5x+A)-x

Find the zeros of solvefor B,x^2-5x+A=(x+B)^2

The zeros of solvefor B,x^2-5x+A=(x+B)^2 are B=sqrt(x^2-5x+A)-x,B=-sqrt(x^2-5x+A)-x

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solve for

B, x^{2} - 5 x + A = (x + B)^{2}

B = x^{2} - 5 x + A - x, B = - x^{2} - 5 x + A - x

Solution steps

x^{2} - 5 x + A = (x + B)^{2}

Switch sides

(x + B)^{2} = x^{2} - 5 x + A

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + B = x^{2} - 5 x + A : B = x^{2} - 5 x + A - x

Solve

x + B = - x^{2} - 5 x + A : B = - x^{2} - 5 x + A - x

The solutions to the quadratic equation are:

B = x^{2} - 5 x + A - x, B = - x^{2} - 5 x + A - x

(x + 4)^{2} + 7 = 0

3 t^{2} - 60 t = 0

m^{2} + 3 m + 6 = 0

V, P = \frac{V ^{2}}{R}

3 y^{2} - 36 = 0

What are the solutions to the equation solvefor B,x^2-5x+A=(x+B)^2 ?
The solutions to the equation solvefor B,x^2-5x+A=(x+B)^2 are B=sqrt(x^2-5x+A)-x,B=-sqrt(x^2-5x+A)-x
Find the zeros of solvefor B,x^2-5x+A=(x+B)^2
The zeros of solvefor B,x^2-5x+A=(x+B)^2 are B=sqrt(x^2-5x+A)-x,B=-sqrt(x^2-5x+A)-x