What are the solutions to the equation k^2+4k-95=-8 ?

The solutions to the equation k^2+4k-95=-8 are k=-2+sqrt(91),k=-2-sqrt(91)

Find the zeros of k^2+4k-95=-8

The zeros of k^2+4k-95=-8 are k=-2+sqrt(91),k=-2-sqrt(91)

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k^{2} + 4 k - 95 = - 8

k = - 2 + 91, k = - 2 - 91

Decimal Notation

k = 7.53939 \dots, k = - 11.53939 \dots

Solution steps

k^{2} + 4 k - 95 = - 8

Move

8

to the left side

k^{2} + 4 k - 87 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 87 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 87) = 291

k_{1, 2} = \frac{- 4 \pm 2 91}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 4 + 2 91}{2 \cdot 1}, k_{2} = \frac{- 4 - 2 91}{2 \cdot 1}

k = \frac{- 4 + 2 91}{2 \cdot 1} : - 2 + 91

k = \frac{- 4 - 2 91}{2 \cdot 1} : - 2 - 91

The solutions to the quadratic equation are:

k = - 2 + 91, k = - 2 - 91

2 x^{2} - 14 x + 12 = 0

4 x^{2} + 27 x - 40 = 0

x^{2} + 20 x + 100 = 81

3 (g - 1)^{2} + 2 = 0

x^{2} - 10 x + 9 = 0

What are the solutions to the equation k^2+4k-95=-8 ?
The solutions to the equation k^2+4k-95=-8 are k=-2+sqrt(91),k=-2-sqrt(91)
Find the zeros of k^2+4k-95=-8
The zeros of k^2+4k-95=-8 are k=-2+sqrt(91),k=-2-sqrt(91)