What are the solutions to the equation 25y^2+15y+21=0 ?

The solutions to the equation 25y^2+15y+21=0 are y=-3/10+i(sqrt(3))/2 ,y=-3/10-i(sqrt(3))/2

Find the zeros of 25y^2+15y+21=0

The zeros of 25y^2+15y+21=0 are y=-3/10+i(sqrt(3))/2 ,y=-3/10-i(sqrt(3))/2

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25 y^{2} + 15 y + 21 = 0

y = - \frac{3}{10} + i \frac{3}{2}, y = - \frac{3}{10} - i \frac{3}{2}

Solution steps

25 y^{2} + 15 y + 21 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 25 \cdot 21}{2 \cdot 25}

Simplify

1 5^{2} - 4 \cdot 25 \cdot 21 : 253 i

y_{1, 2} = \frac{- 15 \pm 25 3 i}{2 \cdot 25}

Separate the solutions

y_{1} = \frac{- 15 + 25 3 i}{2 \cdot 25}, y_{2} = \frac{- 15 - 25 3 i}{2 \cdot 25}

y = \frac{- 15 + 25 3 i}{2 \cdot 25} : - \frac{3}{10} + i \frac{3}{2}

y = \frac{- 15 - 25 3 i}{2 \cdot 25} : - \frac{3}{10} - i \frac{3}{2}

The solutions to the quadratic equation are:

y = - \frac{3}{10} + i \frac{3}{2}, y = - \frac{3}{10} - i \frac{3}{2}

7 x (1 - x) = 5 (x - 2)

x^{2} - x - 2 = 0

x, x^{2} + 3 x - 2 = 0

(x + 4)^{2} + 50 = 0

k^{2} - 7 k + 6 = 0

What are the solutions to the equation 25y^2+15y+21=0 ?
The solutions to the equation 25y^2+15y+21=0 are y=-3/10+i(sqrt(3))/2 ,y=-3/10-i(sqrt(3))/2
Find the zeros of 25y^2+15y+21=0
The zeros of 25y^2+15y+21=0 are y=-3/10+i(sqrt(3))/2 ,y=-3/10-i(sqrt(3))/2