What are the solutions to the equation 4x^2+3x-24=0 ?

The solutions to the equation 4x^2+3x-24=0 are x=(-3+sqrt(393))/8 ,x=(-3-sqrt(393))/8

Find the zeros of 4x^2+3x-24=0

The zeros of 4x^2+3x-24=0 are x=(-3+sqrt(393))/8 ,x=(-3-sqrt(393))/8

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4 x^{2} + 3 x - 24 = 0

x = \frac{- 3 + 393}{8}, x = \frac{- 3 - 393}{8}

Decimal Notation

x = 2.10302 \dots, x = - 2.85302 \dots

Solution steps

4 x^{2} + 3 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 24) = 393

x_{1, 2} = \frac{- 3 \pm 393}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 393}{2 \cdot 4}, x_{2} = \frac{- 3 - 393}{2 \cdot 4}

x = \frac{- 3 + 393}{2 \cdot 4} : \frac{- 3 + 393}{8}

x = \frac{- 3 - 393}{2 \cdot 4} : \frac{- 3 - 393}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 393}{8}, x = \frac{- 3 - 393}{8}

s^{2} - s - 6 = 0

4 x^{2} - 2 x = x^{2} + 2 x + 5

x (x - 2 a + 1) + a^{2} - 1 = 0

y^{2} + 9 y - 22 = 0

x^{2} - 2021 x + 7 (x - 2021) = 0

What are the solutions to the equation 4x^2+3x-24=0 ?
The solutions to the equation 4x^2+3x-24=0 are x=(-3+sqrt(393))/8 ,x=(-3-sqrt(393))/8
Find the zeros of 4x^2+3x-24=0
The zeros of 4x^2+3x-24=0 are x=(-3+sqrt(393))/8 ,x=(-3-sqrt(393))/8