What are the solutions to the equation s^2-s-6=0 ?

The solutions to the equation s^2-s-6=0 are s=3,s=-2

Find the zeros of s^2-s-6=0

The zeros of s^2-s-6=0 are s=3,s=-2

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s^{2} - s - 6 = 0

s = 3, s = - 2

Solution steps

s^{2} - s - 6 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

s_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, s_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

s = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

s = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

s = 3, s = - 2

4 x^{2} - 2 x = x^{2} + 2 x + 5

x (x - 2 a + 1) + a^{2} - 1 = 0

y^{2} + 9 y - 22 = 0

x^{2} - 2021 x + 7 (x - 2021) = 0

p^{2} - 2 p - 24 = 0

What are the solutions to the equation s^2-s-6=0 ?
The solutions to the equation s^2-s-6=0 are s=3,s=-2
Find the zeros of s^2-s-6=0
The zeros of s^2-s-6=0 are s=3,s=-2