What are the solutions to the equation x^2-20x+80=0 ?

The solutions to the equation x^2-20x+80=0 are x=2(5+sqrt(5)),x=2(5-sqrt(5))

Find the zeros of x^2-20x+80=0

The zeros of x^2-20x+80=0 are x=2(5+sqrt(5)),x=2(5-sqrt(5))

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x^{2} - 20 x + 80 = 0

x = 2 (5 + 5), x = 2 (5 - 5)

Decimal Notation

x = 14.47213 \dots, x = 5.52786 \dots

Solution steps

x^{2} - 20 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 80}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 80 = 45

x_{1, 2} = \frac{- ( - 20 ) \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 5}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 4 5}{2 \cdot 1}

x = \frac{- ( - 20 ) + 4 5}{2 \cdot 1} : 2 (5 + 5)

x = \frac{- ( - 20 ) - 4 5}{2 \cdot 1} : 2 (5 - 5)

The solutions to the quadratic equation are:

x = 2 (5 + 5), x = 2 (5 - 5)

(m^{2} + 2 m + 2) = 0

(x - 3)^{2} + 1 = 2 x - 5

\frac{1}{4} (2 A) + 2 A x + B + A x^{2} + B x + C = x^{2} - 2 x

0.48 x^{2} - 1.88 x - 1.68 = 0

7 x^{2} - 3 x + j = 0

What are the solutions to the equation x^2-20x+80=0 ?
The solutions to the equation x^2-20x+80=0 are x=2(5+sqrt(5)),x=2(5-sqrt(5))
Find the zeros of x^2-20x+80=0
The zeros of x^2-20x+80=0 are x=2(5+sqrt(5)),x=2(5-sqrt(5))