What are the solutions to the equation 2x^2+10x=-12 ?

The solutions to the equation 2x^2+10x=-12 are x=-2,x=-3

Find the zeros of 2x^2+10x=-12

The zeros of 2x^2+10x=-12 are x=-2,x=-3

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2 x^{2} + 10 x = - 12

x = - 2, x = - 3

Solution steps

2 x^{2} + 10 x = - 12

Move

12

to the left side

2 x^{2} + 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 12 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 2}, x_{2} = \frac{- 10 - 2}{2 \cdot 2}

x = \frac{- 10 + 2}{2 \cdot 2} : - 2

x = \frac{- 10 - 2}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

6 x^{2} - 48 = - 12 x

2 x^{2} - 14 = 27 x

0 = - 16 t^{2} + 32 t + 28

x, x^{2} - 6 y^{2} = x y

2 x^{2} + 2 x + 10 = 0

What are the solutions to the equation 2x^2+10x=-12 ?
The solutions to the equation 2x^2+10x=-12 are x=-2,x=-3
Find the zeros of 2x^2+10x=-12
The zeros of 2x^2+10x=-12 are x=-2,x=-3