What are the solutions to the equation t^2+2t+10=0 ?

The solutions to the equation t^2+2t+10=0 are t=-1+3i,t=-1-3i

Find the zeros of t^2+2t+10=0

The zeros of t^2+2t+10=0 are t=-1+3i,t=-1-3i

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t^{2} + 2 t + 10 = 0

t = - 1 + 3 i, t = - 1 - 3 i

Solution steps

t^{2} + 2 t + 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 10 : 6 i

t_{1, 2} = \frac{- 2 \pm 6 i}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 2 + 6 i}{2 \cdot 1}, t_{2} = \frac{- 2 - 6 i}{2 \cdot 1}

t = \frac{- 2 + 6 i}{2 \cdot 1} : - 1 + 3 i

t = \frac{- 2 - 6 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

t = - 1 + 3 i, t = - 1 - 3 i

2 x^{2} + 10 x = - 12

6 x^{2} - 48 = - 12 x

2 x^{2} - 14 = 27 x

0 = - 16 t^{2} + 32 t + 28

x, x^{2} - 6 y^{2} = x y

What are the solutions to the equation t^2+2t+10=0 ?
The solutions to the equation t^2+2t+10=0 are t=-1+3i,t=-1-3i
Find the zeros of t^2+2t+10=0
The zeros of t^2+2t+10=0 are t=-1+3i,t=-1-3i