What are the solutions to the equation completesquare x^2-10x+12=0 ?

The solutions to the equation completesquare x^2-10x+12=0 are x=sqrt(13)+5,x=-sqrt(13)+5

Find the zeros of completesquare x^2-10x+12=0

The zeros of completesquare x^2-10x+12=0 are x=sqrt(13)+5,x=-sqrt(13)+5

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x^{2} - 10 x + 12 = 0

x = 13 + 5, x = - 13 + 5

Decimal Notation

x = 8.60555 \dots, x = 1.39444 \dots

Solution steps

x^{2} - 10 x + 12 = 0

Move

12

to the right side

x^{2} - 10 x = - 12

Rewrite in the form

(x + a)^{2} = b

(x - 5)^{2} = 13

For

the solutions are

f (x) = a, - a

Solve

x - 5 = 13 : x = 13 + 5

Solve

x - 5 = - 13 : x = - 13 + 5

The solutions to the quadratic equation are:

x = 13 + 5, x = - 13 + 5

\frac{x ^{2} - 3 x}{2} - 5 = \frac{x - 20}{4}

2 x^{2} + 7 x - 9 = - 5

x^{2} + 0.54 x - 0.27 = 0

- x^{2} + 14 x + 74 = 0

3 x^{2} + 5 x = 2

What are the solutions to the equation completesquare x^2-10x+12=0 ?
The solutions to the equation completesquare x^2-10x+12=0 are x=sqrt(13)+5,x=-sqrt(13)+5
Find the zeros of completesquare x^2-10x+12=0
The zeros of completesquare x^2-10x+12=0 are x=sqrt(13)+5,x=-sqrt(13)+5