What are the solutions to the equation s^2-8s+16=0 ?

The solutions to the equation s^2-8s+16=0 are s=4

Find the zeros of s^2-8s+16=0

The zeros of s^2-8s+16=0 are s=4

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s^{2} - 8 s + 16 = 0

s = 4

Solution steps

s^{2} - 8 s + 16 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

s_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

s = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

s = 4

The solution to the quadratic equation is:

s = 4

3 n^{2} - 19 n + 42 = 6 n

9 x^{2} = - 42 x - 52

- (x^{2} + 4) = 0

4 u^{2} - 28 u = 0

k, x = \frac{1}{2} (k^{2} - 1)

What are the solutions to the equation s^2-8s+16=0 ?
The solutions to the equation s^2-8s+16=0 are s=4
Find the zeros of s^2-8s+16=0
The zeros of s^2-8s+16=0 are s=4