What are the solutions to the equation x^2+x+5/4 =0 ?

The solutions to the equation x^2+x+5/4 =0 are x=-1/2+i,x=-1/2-i

Find the zeros of x^2+x+5/4 =0

The zeros of x^2+x+5/4 =0 are x=-1/2+i,x=-1/2-i

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x^{2} + x + \frac{5}{4} = 0

x = - \frac{1}{2} + i, x = - \frac{1}{2} - i

Solution steps

x^{2} + x + \frac{5}{4} = 0

Multiply both sides by

4

4 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

Simplify

4^{2} - 4 \cdot 4 \cdot 5 : 8 i

x_{1, 2} = \frac{- 4 \pm 8 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8 i}{2 \cdot 4}, x_{2} = \frac{- 4 - 8 i}{2 \cdot 4}

x = \frac{- 4 + 8 i}{2 \cdot 4} : - \frac{1}{2} + i

x = \frac{- 4 - 8 i}{2 \cdot 4} : - \frac{1}{2} - i

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i, x = - \frac{1}{2} - i

x^{2} = 2^{2} + (23)^{2}

x^{2} + 2 x + 4 = 0

2 y^{2} - 3 y - 2 = 0

x^{2} + x - 99 = 0

p^{2} + 5 = 6 p

What are the solutions to the equation x^2+x+5/4 =0 ?
The solutions to the equation x^2+x+5/4 =0 are x=-1/2+i,x=-1/2-i
Find the zeros of x^2+x+5/4 =0
The zeros of x^2+x+5/4 =0 are x=-1/2+i,x=-1/2-i