What are the solutions to the equation x^2=2^2+(2sqrt(3))^2 ?

The solutions to the equation x^2=2^2+(2sqrt(3))^2 are x=4,x=-4

Find the zeros of x^2=2^2+(2sqrt(3))^2

The zeros of x^2=2^2+(2sqrt(3))^2 are x=4,x=-4

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x^{2} = 2^{2} + (23)^{2}

x = 4, x = - 4

Solution steps

x^{2} = 2^{2} + (23)^{2}

Simplify

2^{2} + (23)^{2} : 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

x^{2} + 2 x + 4 = 0

2 y^{2} - 3 y - 2 = 0

x^{2} + x - 99 = 0

p^{2} + 5 = 6 p

x^{2} + 10 x + 16 = 0

What are the solutions to the equation x^2=2^2+(2sqrt(3))^2 ?
The solutions to the equation x^2=2^2+(2sqrt(3))^2 are x=4,x=-4
Find the zeros of x^2=2^2+(2sqrt(3))^2
The zeros of x^2=2^2+(2sqrt(3))^2 are x=4,x=-4