What are the solutions to the equation -2x^2+3x+8=0 ?

The solutions to the equation -2x^2+3x+8=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4

Find the zeros of -2x^2+3x+8=0

The zeros of -2x^2+3x+8=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4

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- 2 x^{2} + 3 x + 8 = 0

x = - \frac{- 3 + 73}{4}, x = \frac{3 + 73}{4}

Decimal Notation

x = - 1.38600 \dots, x = 2.88600 \dots

Solution steps

- 2 x^{2} + 3 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 8}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 8 = 73

x_{1, 2} = \frac{- 3 \pm 73}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 73}{2 ( - 2 )}, x_{2} = \frac{- 3 - 73}{2 ( - 2 )}

x = \frac{- 3 + 73}{2 ( - 2 )} : - \frac{- 3 + 73}{4}

x = \frac{- 3 - 73}{2 ( - 2 )} : \frac{3 + 73}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 73}{4}, x = \frac{3 + 73}{4}

0 = 12 x^{2} - 280 x + 1000

x, x^{2} - 2 x y + y^{2} = 6

(x - 4)^{2} = - 16

(2 x - 3) (x + 4) = 6

x^{2} - 10 x = - 9 x - 1

What are the solutions to the equation -2x^2+3x+8=0 ?
The solutions to the equation -2x^2+3x+8=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4
Find the zeros of -2x^2+3x+8=0
The zeros of -2x^2+3x+8=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4