What are the solutions to the equation solvefor x,x^2-2xy+y^2=6 ?

The solutions to the equation solvefor x,x^2-2xy+y^2=6 are x=y+sqrt(6),x=y-sqrt(6)

Find the zeros of solvefor x,x^2-2xy+y^2=6

The zeros of solvefor x,x^2-2xy+y^2=6 are x=y+sqrt(6),x=y-sqrt(6)

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solve for

x, x^{2} - 2 x y + y^{2} = 6

x = y + 6, x = y - 6

Solution steps

x^{2} - 2 x y + y^{2} = 6

Move

6

to the left side

x^{2} - 2 x y + y^{2} - 6 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 y x + y^{2} - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 y ) \pm ( - 2 y ) ^{2} - 4 \cdot 1 \cdot ( y ^{2} - 6 )}{2 \cdot 1}

(- 2 y)^{2} - 4 \cdot 1 \cdot (y^{2} - 6) = 26

x_{1, 2} = \frac{- ( - 2 y ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 y ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 y ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 2 y ) + 2 6}{2 \cdot 1} : y + 6

x = \frac{- ( - 2 y ) - 2 6}{2 \cdot 1} : y - 6

The solutions to the quadratic equation are:

x = y + 6, x = y - 6

(x - 4)^{2} = - 16

(2 x - 3) (x + 4) = 6

x^{2} - 10 x = - 9 x - 1

(x + 6) x = 720

x^{2} + 18 x = 15

What are the solutions to the equation solvefor x,x^2-2xy+y^2=6 ?
The solutions to the equation solvefor x,x^2-2xy+y^2=6 are x=y+sqrt(6),x=y-sqrt(6)
Find the zeros of solvefor x,x^2-2xy+y^2=6
The zeros of solvefor x,x^2-2xy+y^2=6 are x=y+sqrt(6),x=y-sqrt(6)