What are the solutions to the equation 5x^2+7x+3=0 ?

The solutions to the equation 5x^2+7x+3=0 are x=-7/10+i(sqrt(11))/(10),x=-7/10-i(sqrt(11))/(10)

Find the zeros of 5x^2+7x+3=0

The zeros of 5x^2+7x+3=0 are x=-7/10+i(sqrt(11))/(10),x=-7/10-i(sqrt(11))/(10)

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5 x^{2} + 7 x + 3 = 0

x = - \frac{7}{10} + i \frac{11}{10}, x = - \frac{7}{10} - i \frac{11}{10}

Solution steps

5 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

Simplify

7^{2} - 4 \cdot 5 \cdot 3 : 11 i

x_{1, 2} = \frac{- 7 \pm 11 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 11 i}{2 \cdot 5}, x_{2} = \frac{- 7 - 11 i}{2 \cdot 5}

x = \frac{- 7 + 11 i}{2 \cdot 5} : - \frac{7}{10} + i \frac{11}{10}

x = \frac{- 7 - 11 i}{2 \cdot 5} : - \frac{7}{10} - i \frac{11}{10}

The solutions to the quadratic equation are:

x = - \frac{7}{10} + i \frac{11}{10}, x = - \frac{7}{10} - i \frac{11}{10}

X^{2} + 15 X + 56 = 0

x^{2} - 6 x = - 13

x, 12 x^{2} + 12 x y + 7 y^{2} - 4 x + 6 y - 1 = 0

(213)^{2} + y^{2} = 1 3^{2}

x, x^{2} + x y + 4 y^{2} = 6

What are the solutions to the equation 5x^2+7x+3=0 ?
The solutions to the equation 5x^2+7x+3=0 are x=-7/10+i(sqrt(11))/(10),x=-7/10-i(sqrt(11))/(10)
Find the zeros of 5x^2+7x+3=0
The zeros of 5x^2+7x+3=0 are x=-7/10+i(sqrt(11))/(10),x=-7/10-i(sqrt(11))/(10)