What are the solutions to the equation X^2+15X+56=0 ?

The solutions to the equation X^2+15X+56=0 are X=-7,X=-8

Find the zeros of X^2+15X+56=0

The zeros of X^2+15X+56=0 are X=-7,X=-8

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X^{2} + 15 X + 56 = 0

X = - 7, X = - 8

Solution steps

X^{2} + 15 X + 56 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 56 = 1

X_{1, 2} = \frac{- 15 \pm 1}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 15 + 1}{2 \cdot 1}, X_{2} = \frac{- 15 - 1}{2 \cdot 1}

X = \frac{- 15 + 1}{2 \cdot 1} : - 7

X = \frac{- 15 - 1}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

X = - 7, X = - 8

x^{2} - 6 x = - 13

x, 12 x^{2} + 12 x y + 7 y^{2} - 4 x + 6 y - 1 = 0

(213)^{2} + y^{2} = 1 3^{2}

x, x^{2} + x y + 4 y^{2} = 6

12 x^{2} = 5 + 10 x

What are the solutions to the equation X^2+15X+56=0 ?
The solutions to the equation X^2+15X+56=0 are X=-7,X=-8
Find the zeros of X^2+15X+56=0
The zeros of X^2+15X+56=0 are X=-7,X=-8