What are the solutions to the equation x^2+sqrt(3)^2=2^2 ?

The solutions to the equation x^2+sqrt(3)^2=2^2 are x=1,x=-1

Find the zeros of x^2+sqrt(3)^2=2^2

The zeros of x^2+sqrt(3)^2=2^2 are x=1,x=-1

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x^{2} + 3^{2} = 2^{2}

x = 1, x = - 1

Solution steps

x^{2} + (3)^{2} = 2^{2}

Move

3^{2}

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

x, y - ln (y) = x^{2} + 1

4 - 2 x^{2} = 12

14.59 \cdot 0.6 \cdot t - \frac{1}{2} \cdot 5 \cdot t^{2} = 1

y, 4 x^{2} + y^{2} = 4

x^{2} - 20 x + 12 = 0

What are the solutions to the equation x^2+sqrt(3)^2=2^2 ?
The solutions to the equation x^2+sqrt(3)^2=2^2 are x=1,x=-1
Find the zeros of x^2+sqrt(3)^2=2^2
The zeros of x^2+sqrt(3)^2=2^2 are x=1,x=-1