What are the solutions to the equation -1/2 (x+1)^2+8=-1 ?

The solutions to the equation -1/2 (x+1)^2+8=-1 are x=3sqrt(2)-1,x=-3sqrt(2)-1

Find the zeros of -1/2 (x+1)^2+8=-1

The zeros of -1/2 (x+1)^2+8=-1 are x=3sqrt(2)-1,x=-3sqrt(2)-1

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- \frac{1}{2} (x + 1)^{2} + 8 = - 1

x = 32 - 1, x = - 32 - 1

Decimal Notation

x = 3.24264 \dots, x = - 5.24264 \dots

Solution steps

- \frac{1}{2} (x + 1)^{2} + 8 = - 1

Move

8

to the right side

- \frac{1}{2} (x + 1)^{2} = - 9

Multiply both sides by

- 2

(x + 1)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 18 : x = 32 - 1

Solve

x + 1 = - 18 : x = - 32 - 1

The solutions to the quadratic equation are:

x = 32 - 1, x = - 32 - 1

x^{2} + 2 x + 63 = 0

4 x^{2} + 20 x = 2

0 = 3 x^{2} - 36 x + 81

2 n^{2} + 2 n - 84 = 0

b^{2} + 6 b - 7 = 0

What are the solutions to the equation -1/2 (x+1)^2+8=-1 ?
The solutions to the equation -1/2 (x+1)^2+8=-1 are x=3sqrt(2)-1,x=-3sqrt(2)-1
Find the zeros of -1/2 (x+1)^2+8=-1
The zeros of -1/2 (x+1)^2+8=-1 are x=3sqrt(2)-1,x=-3sqrt(2)-1