What are the solutions to the equation x^2+2x+63=0 ?

The solutions to the equation x^2+2x+63=0 are x=-1+sqrt(62)i,x=-1-sqrt(62)i

Find the zeros of x^2+2x+63=0

The zeros of x^2+2x+63=0 are x=-1+sqrt(62)i,x=-1-sqrt(62)i

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x^{2} + 2 x + 63 = 0

x = - 1 + 62 i, x = - 1 - 62 i

Solution steps

x^{2} + 2 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 63}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 63 : 262 i

x_{1, 2} = \frac{- 2 \pm 2 62 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 62 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 62 i}{2 \cdot 1}

x = \frac{- 2 + 2 62 i}{2 \cdot 1} : - 1 + 62 i

x = \frac{- 2 - 2 62 i}{2 \cdot 1} : - 1 - 62 i

The solutions to the quadratic equation are:

x = - 1 + 62 i, x = - 1 - 62 i

4 x^{2} + 20 x = 2

0 = 3 x^{2} - 36 x + 81

2 n^{2} + 2 n - 84 = 0

b^{2} + 6 b - 7 = 0

6 x^{2} + 23 x = 13

What are the solutions to the equation x^2+2x+63=0 ?
The solutions to the equation x^2+2x+63=0 are x=-1+sqrt(62)i,x=-1-sqrt(62)i
Find the zeros of x^2+2x+63=0
The zeros of x^2+2x+63=0 are x=-1+sqrt(62)i,x=-1-sqrt(62)i