What are the solutions to the equation 4((x+1)/2)^2-5=0 ?

The solutions to the equation 4((x+1)/2)^2-5=0 are x=sqrt(5)-1,x=-sqrt(5)-1

Find the zeros of 4((x+1)/2)^2-5=0

The zeros of 4((x+1)/2)^2-5=0 are x=sqrt(5)-1,x=-sqrt(5)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (\frac{x + 1}{2})^{2} - 5 = 0

x = 5 - 1, x = - 5 - 1

Decimal Notation

x = 1.23606 \dots, x = - 3.23606 \dots

Solution steps

4 (\frac{x + 1}{2})^{2} - 5 = 0

Move

5

to the right side

4 (\frac{x + 1}{2})^{2} = 5

Divide both sides by

4

(\frac{x + 1}{2})^{2} = \frac{5}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{x + 1}{2} = \frac{5}{4} : x = 5 - 1

Solve

\frac{x + 1}{2} = - \frac{5}{4} : x = - 5 - 1

The solutions to the quadratic equation are:

x = 5 - 1, x = - 5 - 1

x^{2} + 20 x - 20 = 0

b^{2} - 18 b - 24 = 9 - 4 b

x (x - 17) = - 60

6 x^{2} + 19 x = 20

46.39 = 46.8 + 30.2 t - 4.9 t^{2}

What are the solutions to the equation 4((x+1)/2)^2-5=0 ?
The solutions to the equation 4((x+1)/2)^2-5=0 are x=sqrt(5)-1,x=-sqrt(5)-1
Find the zeros of 4((x+1)/2)^2-5=0
The zeros of 4((x+1)/2)^2-5=0 are x=sqrt(5)-1,x=-sqrt(5)-1