What are the solutions to the equation -x^2+6x-16=0 ?

The solutions to the equation -x^2+6x-16=0 are x=3-sqrt(7)i,x=3+sqrt(7)i

Find the zeros of -x^2+6x-16=0

The zeros of -x^2+6x-16=0 are x=3-sqrt(7)i,x=3+sqrt(7)i

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- x^{2} + 6 x - 16 = 0

x = 3 - 7 i, x = 3 + 7 i

Solution steps

- x^{2} + 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

Simplify

6^{2} - 4 (- 1) (- 16) : 27 i

x_{1, 2} = \frac{- 6 \pm 2 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 7 i}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 7 i}{2 ( - 1 )}

x = \frac{- 6 + 2 7 i}{2 ( - 1 )} : 3 - 7 i

x = \frac{- 6 - 2 7 i}{2 ( - 1 )} : 3 + 7 i

The solutions to the quadratic equation are:

x = 3 - 7 i, x = 3 + 7 i

3 x^{2} - 76 = 71

- 6 - 5 x^{2} + 13 x = 5 x + 5

p = - 500 p^{2} + 67000 p - 20000

- 3 b^{2} - 4 = 26

3 x^{2} + 21 x + 30 = 0

What are the solutions to the equation -x^2+6x-16=0 ?
The solutions to the equation -x^2+6x-16=0 are x=3-sqrt(7)i,x=3+sqrt(7)i
Find the zeros of -x^2+6x-16=0
The zeros of -x^2+6x-16=0 are x=3-sqrt(7)i,x=3+sqrt(7)i