What are the solutions to the equation -3b^2-4=26 ?

The solutions to the equation -3b^2-4=26 are b=sqrt(10)i,b=-sqrt(10)i

Find the zeros of -3b^2-4=26

The zeros of -3b^2-4=26 are b=sqrt(10)i,b=-sqrt(10)i

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- 3 b^{2} - 4 = 26

b = 10 i, b = - 10 i

Solution steps

- 3 b^{2} - 4 = 26

Move

4

to the right side

- 3 b^{2} = 30

Divide both sides by

- 3

b^{2} = - 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = - 10, b = - - 10

- 10 = 10 i

- - 10 = - 10 i

b = 10 i, b = - 10 i

3 x^{2} + 21 x + 30 = 0

x^{2} - 5 x + 2 = 0

x^{2} + 18 x = 7

x^{2} - 14 x - 12 = 4

m^{2} + 12 = 0

What are the solutions to the equation -3b^2-4=26 ?
The solutions to the equation -3b^2-4=26 are b=sqrt(10)i,b=-sqrt(10)i
Find the zeros of -3b^2-4=26
The zeros of -3b^2-4=26 are b=sqrt(10)i,b=-sqrt(10)i