What are the solutions to the equation -6-5x^2+13x=5x+5 ?

The solutions to the equation -6-5x^2+13x=5x+5 are x= 4/5-i(sqrt(39))/5 ,x= 4/5+i(sqrt(39))/5

Find the zeros of -6-5x^2+13x=5x+5

The zeros of -6-5x^2+13x=5x+5 are x= 4/5-i(sqrt(39))/5 ,x= 4/5+i(sqrt(39))/5

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- 6 - 5 x^{2} + 13 x = 5 x + 5

x = \frac{4}{5} - i \frac{39}{5}, x = \frac{4}{5} + i \frac{39}{5}

Solution steps

- 6 - 5 x^{2} + 13 x = 5 x + 5

Move

5

to the left side

- 5 x^{2} + 13 x - 11 = 5 x

Move

5 x

to the left side

- 5 x^{2} + 8 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 5 ) ( - 11 )}{2 ( - 5 )}

Simplify

8^{2} - 4 (- 5) (- 11) : 239 i

x_{1, 2} = \frac{- 8 \pm 2 39 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 39 i}{2 ( - 5 )}, x_{2} = \frac{- 8 - 2 39 i}{2 ( - 5 )}

x = \frac{- 8 + 2 39 i}{2 ( - 5 )} : \frac{4}{5} - i \frac{39}{5}

x = \frac{- 8 - 2 39 i}{2 ( - 5 )} : \frac{4}{5} + i \frac{39}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5} - i \frac{39}{5}, x = \frac{4}{5} + i \frac{39}{5}

p = - 500 p^{2} + 67000 p - 20000

- 3 b^{2} - 4 = 26

3 x^{2} + 21 x + 30 = 0

x^{2} - 5 x + 2 = 0

x^{2} + 18 x = 7

What are the solutions to the equation -6-5x^2+13x=5x+5 ?
The solutions to the equation -6-5x^2+13x=5x+5 are x= 4/5-i(sqrt(39))/5 ,x= 4/5+i(sqrt(39))/5
Find the zeros of -6-5x^2+13x=5x+5
The zeros of -6-5x^2+13x=5x+5 are x= 4/5-i(sqrt(39))/5 ,x= 4/5+i(sqrt(39))/5