What are the solutions to the equation -3/4 x^2+9x-34=0 ?

The solutions to the equation -3/4 x^2+9x-34=0 are x=6-i(2sqrt(21))/3 ,x=6+i(2sqrt(21))/3

Find the zeros of -3/4 x^2+9x-34=0

The zeros of -3/4 x^2+9x-34=0 are x=6-i(2sqrt(21))/3 ,x=6+i(2sqrt(21))/3

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- \frac{3}{4} x^{2} + 9 x - 34 = 0

x = 6 - i \frac{2 21}{3}, x = 6 + i \frac{2 21}{3}

Solution steps

- \frac{3}{4} x^{2} + 9 x - 34 = 0

Multiply both sides by

4

- 3 x^{2} + 36 x - 136 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 3 ) ( - 136 )}{2 ( - 3 )}

Simplify

3 6^{2} - 4 (- 3) (- 136) : 421 i

x_{1, 2} = \frac{- 36 \pm 4 21 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 36 + 4 21 i}{2 ( - 3 )}, x_{2} = \frac{- 36 - 4 21 i}{2 ( - 3 )}

x = \frac{- 36 + 4 21 i}{2 ( - 3 )} : 6 - i \frac{2 21}{3}

x = \frac{- 36 - 4 21 i}{2 ( - 3 )} : 6 + i \frac{2 21}{3}

The solutions to the quadratic equation are:

x = 6 - i \frac{2 21}{3}, x = 6 + i \frac{2 21}{3}

5 (x + 2)^{2} + 125 = 0

11 x^{2} = - 121 x

x^{2} - 5 x + 5 = 0

x, x - x^{2} - x y = 0

2 x^{2} = - x - 1

What are the solutions to the equation -3/4 x^2+9x-34=0 ?
The solutions to the equation -3/4 x^2+9x-34=0 are x=6-i(2sqrt(21))/3 ,x=6+i(2sqrt(21))/3
Find the zeros of -3/4 x^2+9x-34=0
The zeros of -3/4 x^2+9x-34=0 are x=6-i(2sqrt(21))/3 ,x=6+i(2sqrt(21))/3