What are the solutions to the equation -3x^2-3x=0 ?

The solutions to the equation -3x^2-3x=0 are x=-1,x=0

Find the zeros of -3x^2-3x=0

The zeros of -3x^2-3x=0 are x=-1,x=0

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- 3 x^{2} - 3 x = 0

x = - 1, x = 0

Solution steps

- 3 x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

(- 3)^{2} - 4 (- 3) \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 ( - 3 )}, x_{2} = \frac{- ( - 3 ) - 3}{2 ( - 3 )}

x = \frac{- ( - 3 ) + 3}{2 ( - 3 )} : - 1

x = \frac{- ( - 3 ) - 3}{2 ( - 3 )} : 0

The solutions to the quadratic equation are:

x = - 1, x = 0

8 x^{2} + 18 x - 24 = 0

6 r^{2} - 7 r + 2 = 0

8 (6 - x) - 3 x (6 - x) = 0

y, y^{2} - x^{2} y + 3 x^{3} = 4

x^{2} + 2 x - 7 = 0

What are the solutions to the equation -3x^2-3x=0 ?
The solutions to the equation -3x^2-3x=0 are x=-1,x=0
Find the zeros of -3x^2-3x=0
The zeros of -3x^2-3x=0 are x=-1,x=0