What are the solutions to the equation -t^2-1=0 ?

The solutions to the equation -t^2-1=0 are t=i,t=-i

Find the zeros of -t^2-1=0

The zeros of -t^2-1=0 are t=i,t=-i

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- t^{2} - 1 = 0

t = i, t = - i

Solution steps

- t^{2} - 1 = 0

Move

1

to the right side

- t^{2} = 1

Divide both sides by

- 1

t^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - 1, t = - - 1

- 1 = i

- - 1 = - i

t = i, t = - i

1 = 2 π \cdot r^{2}

20 x^{2} = 10 x

d^{2} + (- 5) = - 2

u^{2} = - 5

4 x^{2} - 4 x + 5

What are the solutions to the equation -t^2-1=0 ?
The solutions to the equation -t^2-1=0 are t=i,t=-i
Find the zeros of -t^2-1=0
The zeros of -t^2-1=0 are t=i,t=-i