What are the solutions to the equation -1/2 x^2-5=0 ?

The solutions to the equation -1/2 x^2-5=0 are x=sqrt(10)i,x=-sqrt(10)i

Find the zeros of -1/2 x^2-5=0

The zeros of -1/2 x^2-5=0 are x=sqrt(10)i,x=-sqrt(10)i

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- \frac{1}{2} x^{2} - 5 = 0

x = 10 i, x = - 10 i

Solution steps

- \frac{1}{2} x^{2} - 5 = 0

Move

5

to the right side

- \frac{1}{2} x^{2} = 5

Multiply both sides by

- 2

x^{2} = - 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 10, x = - - 10

- 10 = 10 i

- - 10 = - 10 i

x = 10 i, x = - 10 i

a, a^{2} + b c = 1

0 = - x^{2} + x + 12

- 5 \cdot t^{2} + 80 \cdot t = 0

- 12 x^{2} = - 32 x^{2}

12 x + 12 = 16 x^{2} - 16 x + 4

What are the solutions to the equation -1/2 x^2-5=0 ?
The solutions to the equation -1/2 x^2-5=0 are x=sqrt(10)i,x=-sqrt(10)i
Find the zeros of -1/2 x^2-5=0
The zeros of -1/2 x^2-5=0 are x=sqrt(10)i,x=-sqrt(10)i