What are the solutions to the equation x^2+14x-21=10,xx^2+14x-21=10x ?

The solutions to the equation x^2+14x-21=10,xx^2+14x-21=10x are x=-7+4sqrt(5),x=-7-4sqrt(5)

Find the zeros of x^2+14x-21=10,xx^2+14x-21=10x

The zeros of x^2+14x-21=10,xx^2+14x-21=10x are x=-7+4sqrt(5),x=-7-4sqrt(5)

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x^{2} + 14 x - 21 = 10, x x^{2} + 14 x - 21 = 10 x

x = - 7 + 45, x = - 7 - 45

Decimal Notation

x = 1.94427 \dots, x = - 15.94427 \dots

Solution steps

x^{2} + 14 x - 21 = 10

Move

10

to the left side

x^{2} + 14 x - 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 31 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 31) = 85

x_{1, 2} = \frac{- 14 \pm 8 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 8 5}{2 \cdot 1}, x_{2} = \frac{- 14 - 8 5}{2 \cdot 1}

x = \frac{- 14 + 8 5}{2 \cdot 1} : - 7 + 45

x = \frac{- 14 - 8 5}{2 \cdot 1} : - 7 - 45

The solutions to the quadratic equation are:

x = - 7 + 45, x = - 7 - 45

x, lo g_{10} (y) = (x - 2)^{2}

x^{2} = - 9 x + 8

(- 3)^{2} + y^{2} = 7^{2}

x^{2} - \frac{x}{2} = 0

12 x^{2} - 46 = 0

What are the solutions to the equation x^2+14x-21=10,xx^2+14x-21=10x ?
The solutions to the equation x^2+14x-21=10,xx^2+14x-21=10x are x=-7+4sqrt(5),x=-7-4sqrt(5)
Find the zeros of x^2+14x-21=10,xx^2+14x-21=10x
The zeros of x^2+14x-21=10,xx^2+14x-21=10x are x=-7+4sqrt(5),x=-7-4sqrt(5)