What are the solutions to the equation -31z=-49z^2 ?

The solutions to the equation -31z=-49z^2 are z=0,z= 31/49

Find the zeros of -31z=-49z^2

The zeros of -31z=-49z^2 are z=0,z= 31/49

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- 31 z = - 49 z^{2}

z = 0, z = \frac{31}{49}

Decimal Notation

z = 0, z = 0.63265 \dots

Solution steps

- 31 z = - 49 z^{2}

Move

49 z^{2}

to the left side

- 31 z + 49 z^{2} = 0

Factor

- 31 z + 49 z^{2} : z (49 z - 31)

z (49 z - 31) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

z = 0 or 49 z - 31 = 0

Solve

49 z - 31 = 0 : z = \frac{31}{49}

The solutions to the quadratic equation are:

z = 0, z = \frac{31}{49}

x^{2} + 4 x + c = 0

5 x^{2} - 3 x + a - 1 = 0.7

x, x^{2} + y^{2} + 4 x - 3 y + 9 = 0

x^{2} - 17 + 52 = 0

0.25 s^{2} + 1.5 s + 2 - 1 = 0

What are the solutions to the equation -31z=-49z^2 ?
The solutions to the equation -31z=-49z^2 are z=0,z= 31/49
Find the zeros of -31z=-49z^2
The zeros of -31z=-49z^2 are z=0,z= 31/49