What are the solutions to the equation 3x^2+27x+54=-(3x^2)/2-(27x)/2-27 ?

The solutions to the equation 3x^2+27x+54=-(3x^2)/2-(27x)/2-27 are x=-3,x=-6

Find the zeros of 3x^2+27x+54=-(3x^2)/2-(27x)/2-27

The zeros of 3x^2+27x+54=-(3x^2)/2-(27x)/2-27 are x=-3,x=-6

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3 x^{2} + 27 x + 54 = - \frac{3 x ^{2}}{2} - \frac{27 x}{2} - 27

x = - 3, x = - 6

Solution steps

3 x^{2} + 27 x + 54 = - \frac{3 x ^{2}}{2} - \frac{27 x}{2} - 27

Multiply both sides by

2

6 x^{2} + 54 x + 108 = - 3 x^{2} - 27 x - 54

Move

54

to the left side

6 x^{2} + 54 x + 162 = - 3 x^{2} - 27 x

Move

27 x

to the left side

6 x^{2} + 81 x + 162 = - 3 x^{2}

Move

3 x^{2}

to the left side

9 x^{2} + 81 x + 162 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 81 \pm 8 1 ^{2} - 4 \cdot 9 \cdot 162}{2 \cdot 9}

8 1^{2} - 4 \cdot 9 \cdot 162 = 27

x_{1, 2} = \frac{- 81 \pm 27}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 81 + 27}{2 \cdot 9}, x_{2} = \frac{- 81 - 27}{2 \cdot 9}

x = \frac{- 81 + 27}{2 \cdot 9} : - 3

x = \frac{- 81 - 27}{2 \cdot 9} : - 6

The solutions to the quadratic equation are:

x = - 3, x = - 6

t, 48 = 8 (t) + 16 (t)^{2}

x^{2} + \frac{8}{2} x + \frac{15}{4} = 0

p^{2} + 9 p = 0

3 x^{2} + 2 x - 8 = 0

4 n^{2} - 3 n - 17 = 5

What are the solutions to the equation 3x^2+27x+54=-(3x^2)/2-(27x)/2-27 ?
The solutions to the equation 3x^2+27x+54=-(3x^2)/2-(27x)/2-27 are x=-3,x=-6
Find the zeros of 3x^2+27x+54=-(3x^2)/2-(27x)/2-27
The zeros of 3x^2+27x+54=-(3x^2)/2-(27x)/2-27 are x=-3,x=-6