What are the solutions to the equation p^2+9p=0 ?

The solutions to the equation p^2+9p=0 are p=0,p=-9

Find the zeros of p^2+9p=0

The zeros of p^2+9p=0 are p=0,p=-9

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p^{2} + 9 p = 0

p = 0, p = - 9

Solution steps

p^{2} + 9 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 0 = 9

p_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 9 + 9}{2 \cdot 1}, p_{2} = \frac{- 9 - 9}{2 \cdot 1}

p = \frac{- 9 + 9}{2 \cdot 1} : 0

p = \frac{- 9 - 9}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

p = 0, p = - 9

3 x^{2} + 2 x - 8 = 0

4 n^{2} - 3 n - 17 = 5

2 x - 1 = x^{2} - 4

x, 5 x^{2} - 45 = 0

0.45 (3.15 - x) (2.14 - x) = x

What are the solutions to the equation p^2+9p=0 ?
The solutions to the equation p^2+9p=0 are p=0,p=-9
Find the zeros of p^2+9p=0
The zeros of p^2+9p=0 are p=0,p=-9