What are the solutions to the equation (v+10)^2=121 ?

The solutions to the equation (v+10)^2=121 are v=1,v=-21

Find the zeros of (v+10)^2=121

The zeros of (v+10)^2=121 are v=1,v=-21

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(v + 10)^{2} = 121

v = 1, v = - 21

Solution steps

(v + 10)^{2} = 121

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

v + 10 = 121 : v = 1

Solve

v + 10 = - 121 : v = - 21

The solutions to the quadratic equation are:

v = 1, v = - 21

x^{2} + 4 x + c

b (x) = (- 84 x^{2} + 1080 x) - (13.4 x^{2} + 360 + 2010)

70 k^{2} + 118 k + 28 = 0

y^{2} - 5 y = 6

y^{2} - 5 y = 7

What are the solutions to the equation (v+10)^2=121 ?
The solutions to the equation (v+10)^2=121 are v=1,v=-21
Find the zeros of (v+10)^2=121
The zeros of (v+10)^2=121 are v=1,v=-21