What are the solutions to the equation 70k^2+118k+28=0 ?

The solutions to the equation 70k^2+118k+28=0 are k=-2/7 ,k=-7/5

Find the zeros of 70k^2+118k+28=0

The zeros of 70k^2+118k+28=0 are k=-2/7 ,k=-7/5

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70 k^{2} + 118 k + 28 = 0

k = - \frac{2}{7}, k = - \frac{7}{5}

Decimal Notation

k = - 0.28571 \dots, k = - 1.4

Solution steps

70 k^{2} + 118 k + 28 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 118 \pm 11 8 ^{2} - 4 \cdot 70 \cdot 28}{2 \cdot 70}

11 8^{2} - 4 \cdot 70 \cdot 28 = 78

k_{1, 2} = \frac{- 118 \pm 78}{2 \cdot 70}

Separate the solutions

k_{1} = \frac{- 118 + 78}{2 \cdot 70}, k_{2} = \frac{- 118 - 78}{2 \cdot 70}

k = \frac{- 118 + 78}{2 \cdot 70} : - \frac{2}{7}

k = \frac{- 118 - 78}{2 \cdot 70} : - \frac{7}{5}

The solutions to the quadratic equation are:

k = - \frac{2}{7}, k = - \frac{7}{5}

y^{2} - 5 y = 6

y^{2} - 5 y = 7

x, (1 - t^{2}) x^{2} - 2 t^{2} x - (t^{2} + 1) = 0

x^{2} + 100 x + 250 = 0

x^{2} - 3 x - 2 = 0

What are the solutions to the equation 70k^2+118k+28=0 ?
The solutions to the equation 70k^2+118k+28=0 are k=-2/7 ,k=-7/5
Find the zeros of 70k^2+118k+28=0
The zeros of 70k^2+118k+28=0 are k=-2/7 ,k=-7/5