What are the solutions to the equation a^2+6a-4=0 ?

The solutions to the equation a^2+6a-4=0 are a=-3+sqrt(13),a=-3-sqrt(13)

Find the zeros of a^2+6a-4=0

The zeros of a^2+6a-4=0 are a=-3+sqrt(13),a=-3-sqrt(13)

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a^{2} + 6 a - 4 = 0

a = - 3 + 13, a = - 3 - 13

Decimal Notation

a = 0.60555 \dots, a = - 6.60555 \dots

Solution steps

a^{2} + 6 a - 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 4) = 213

a_{1, 2} = \frac{- 6 \pm 2 13}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 6 + 2 13}{2 \cdot 1}, a_{2} = \frac{- 6 - 2 13}{2 \cdot 1}

a = \frac{- 6 + 2 13}{2 \cdot 1} : - 3 + 13

a = \frac{- 6 - 2 13}{2 \cdot 1} : - 3 - 13

The solutions to the quadratic equation are:

a = - 3 + 13, a = - 3 - 13

x^{2} + 13 x - 14 = 0

y, x^{2} + 5 y^{2} = - 8

40 t - 5 t^{2} = 75

c (x) = \frac{1}{4} x^{2} + 4 x + 100

4 x^{2} + 20 x - 11 = 0

What are the solutions to the equation a^2+6a-4=0 ?
The solutions to the equation a^2+6a-4=0 are a=-3+sqrt(13),a=-3-sqrt(13)
Find the zeros of a^2+6a-4=0
The zeros of a^2+6a-4=0 are a=-3+sqrt(13),a=-3-sqrt(13)